Web22 mrt. 2024 · Number of letter = n = 4 Since 2A, p1 = 4 Number of words = 4!/2! = 12 Thus, Total no of words starting with A, G, & I = 24 + 12 + 12 = 48 Hence, 49th word will be start from N i.e. N A A G I & remaining four rearrange according to a dictionary Thus, The 50th word is N A A I G Hence the 50th word will be NAAIG WebMATHEMATICS contains 11 letters so they can be arranged by 11! ways but in this word there is some repeating letters M is 2 times,A is 2 times, T is 2 times.

How many words can be formed from the word MATHEMATICS?

Web= 360 Number of ways in case (i) = 60 ⋅ 360 = 21600 Number of ways in case (ii) = 60 ⋅ 360 = 21600 Total ways = 21600 + 21600 = 43200 (ii) All the vowels are together Since all vowels are together, we have to take it as one unit. Considering the consonants as independent things. So, we have 7 units. WebTotal number words in ‘MATHEMATICS’ is 11. Therefore arrangement will be 11! But letter ‘M, T & A’ are repeated twice therefore their arrangement is given by 2! for each letter. … bin mottynew.exe

How many words can you make out of mathematics

WebTotal no. of 8 letters word formed = P (8, 8) = 8! No. of vowels = 3 (i.e., O, A, I) If we consider these three vowels as one letter, then the number of different words = 8 - 3 = 5 + 1 (as 3’s vowels are considered as 1 word) Hence, the total number of 8 letters in which vowel remains together = P (3 × 3) × P (6 × 6) = 3! × 6! = 6 × 720 = 4320 Web28 okt. 2013 · asthmatic, mismatch, attaches, thematic, schemata, matches, atheism, atheist, attache, aitches, chemist, satiate, miasma, attach, attics, asthma, tamest, … Web28 jun. 2024 · If repetition is allowed, the number of words we can form = 4*4*4*4*4 = 1024. (This is because, when repetition is allowed, we can put any of the four unique alphabets at each of the five positions.) If repetition is not allowed, the number of words we can form = 5!/2! = 60. (This is because “P” comes twice.) Quiz of this Question 1. dacia uk used car search